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[jsinterp] Minimally handle arithmetic operator precedence

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Resolves #32066
This commit is contained in:
dirkf
2023-04-21 14:04:30 +01:00
parent 26035bde46
commit 211cbfd5d4
2 changed files with 48 additions and 3 deletions
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11
test/test_jsinterp.py
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@@ -505,6 +505,17 @@ class TestJSInterpreter(unittest.TestCase):
jsi = JSInterpreter('function x(){return 1236566549 << 5}')
self.assertEqual(jsi.call_function('x'), 915423904)
def test_32066(self):
jsi = JSInterpreter("function x(){return Math.pow(3, 5) + new Date('1970-01-01T08:01:42.000+08:00') / 1000 * -239 - -24205;}")
self.assertEqual(jsi.call_function('x'), 70)
def test_unary_operators(self):
jsi = JSInterpreter('function f(){return 2 - - - 2;}')
self.assertEqual(jsi.call_function('f'), 0)
# fails
# jsi = JSInterpreter('function f(){return 2 + - + - - 2;}')
# self.assertEqual(jsi.call_function('f'), 0)
""" # fails so far
def test_packed(self):
jsi = JSInterpreter('''function x(p,a,c,k,e,d){while(c--)if(k[c])p=p.replace(new RegExp('\\b'+c.toString(a)+'\\b','g'),k[c]);return p}''')